Question

Let X be the score on a national test of randomly selected student from West High...

Let X be the score on a national test of randomly selected student from West High School and Y be the score on the same test of a randomly selected student from East High School. Suppose X has a normal distribution with mean 50 and variance 29. Y has a normal distribution with mean 47 and variance 35, and X and Y are independent. If a student from each high school is randomly selected, what is the probability that the student from West high school has a higher test score than the student from East high school?
Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
IQ scores are sometimes modeled as a continuous variable. Let X be the IQ score of...
IQ scores are sometimes modeled as a continuous variable. Let X be the IQ score of a student, to be randomly selected at a University. Suppose that X has the normal distribution with a mean of 110 and a standard deviation of 8. a.) Find the probability that a randomly selected student has an IQ higher than the national average of 100, but lower than 126. b.) What IQ score has a probability of 0.01 of a randomly selected student...
Suppose the random variable X records a randomly selected student’s score on a national test, where...
Suppose the random variable X records a randomly selected student’s score on a national test, where the population distribution for the score is normal with mean 70 and standard deviation 5. A simple random sample of 200 students is taken. (a) What is the distribution of the sample mean score? Is this the exact distribution or an approximated distribution? (b) What is the probability that the sample mean will exceed 71? (c) What is the probability that the sample mean...
200 high school freshmen were randomly selected for a national survey. Among the survey participants, the...
200 high school freshmen were randomly selected for a national survey. Among the survey participants, the mean grade-point average (GPA) was 2.7. If the data follows a normal distribution with a standard deviation of 0.4, what is the margin of error, assuming a 95% confidence level?
A school district has four schools, six class in from each school were randomly selected and...
A school district has four schools, six class in from each school were randomly selected and the number of students in the class were recorded. Test the claim that at least one school has a different class size at a 0.01 level of significance. School A School B School C School D 44 43 37 30 45 50 33 32 49 40 35 35 47 40 32 25 29 47 40 31 32 31 33 29 The hypotheses for this...
QUESTION 7 Let x be a random variable representing the SAT math score of student. We...
QUESTION 7 Let x be a random variable representing the SAT math score of student. We may assume that x has a normal distribution and that the population standard deviation is 25. A large university claims the average SAT math score for incoming freshman is 650. You suspect that this claim is too high and decide to test the claim. You select a random sample of 75 incoming freshman and find the mean SAT math score to be 645.  If you...
) The mean ACT mathematics score for 60 randomly selected high school students is 20.6. Assume...
) The mean ACT mathematics score for 60 randomly selected high school students is 20.6. Assume the population standard deviation is 5.4. The mean ACT science score for 75 other randomly selected high school students is 20.8. Assume the population standard deviation is 5.6. At ? = 0.01, can you reject the claim that the ACT math and ACT science scores are equal? a.) Verify that 1.) Both population standard deviations are known. _____ 2.) The samples taken are random....
7.    (10 pts.) The national mean score for the SAT is 910. An SAT preparation...
7.    (10 pts.) The national mean score for the SAT is 910. An SAT preparation program claims that, on average, its graduates score higher than the national average of 910. To test the program’s claim, 36 students who have applied to take the SAT are selected randomly for inclusion in the prep course. anwsers must be in 4 decimal places a.   What are the hypotheses for the test?                           b.   Let X be the...
6.18 ACT scores of high school seniors. The scores of your state’s high school seniors on...
6.18 ACT scores of high school seniors. The scores of your state’s high school seniors on the ACT college entrance examination in a recent year had mean m 5 22.3 and standard deviation s 5 6.2. The distribution of scores is only roughly Normal. (a) What is the approximate probability that a single student randomly chosen from all those taking the test scores 27 or higher?(b) Now consider an SRS of 16 students who took the test. What are the...
A sample of 25 randomly selected students has a mean test score of 81.5 with a...
A sample of 25 randomly selected students has a mean test score of 81.5 with a standard deviation of 10.2. Assuming that the population has a normal distribution, use this sample data to construct a 95% confidence interval for the population mean μ of all test scores. A. (77.29, 85.71) B. (56.12, 78.34) C. (87.12, 98.32) D. (66.35, 69.89)
Independent Samples T-TEST Two rival schools, West Ridge College and East Ridge College, each claim to...
Independent Samples T-TEST Two rival schools, West Ridge College and East Ridge College, each claim to have a better microbiology program than the other.  The microbiology students at both schools take the same national exam at the end of the year.  Although West Ridge College gets a higher mean score, the East Ridge College’s microbiology professor claims that the difference in scores is too small to be statistically significant.  Here is the data West Ridge College:  Mean or   = 85.8;  12.8;  = 16 East Ridge College:  Mean or   =...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT