A Poisson distribution with m= 1.2 governs the number of fireflies that flash in a 10 second period during an August evening in the yard. Determine the probability that:
A) 2 fireflies flash
B) Less than or equal 3 flash
C) 6 fireflies flash in a 30 second period
Thanks for help :)
in a Poisson distribution p (X=x)= (
given m= average = = 1.2 per10 sec
a) given x= 2 fireflies flash
p (x=2)=( e^-1.2 × 1.2^2) / 2!
=0.2169
b)x=less than or equal 3 flash
then
p (x3)= p (x=0)+p (x=1)+p (x=2)+p (x=3)
= e^-1.2 [ ]
= 0.30119 [ 1+1.2+ 0.72+0.288]
=0.30119 (3.208)
=0.96623
c) x=6 fireflies flash in a 30 sec period
= 1.2 per 10sec
for 30sec =1.2×3 = 3.6
p (x=6)=
= 0.0826
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