4 randomly selected cans of pumpkin pie mix contain a mean of 30 ounces / per can . Verify the claim that an average of pie mix in one can exceeds 31.5 ounces if the contents of the cans are normally distributed with a standard deviation 2 ounces.
List the conditions for testing a population mean, and indicate whether all conditions for test are satisfied here.
Here, we use the one sample t test to test whether the difference between the sample mean and the population mean.
Here, = 30 , s = 2
The population mean, = 31.5
To test,
H0 : The average pie mix is greater than 31.5
H1 : The average pie mix is not greater than 31.5
Here, we take level of significance = 0.05
DF = n-1 = 4-1 = 3
The test statistic is, t = ( - )/( s/n )
= -1.5
At level 0.05, and df = 3, critical value of t = 2.353
As the critical value of t is greater than the test statistic, we reject the null hypothesis at alpha= 0.05.
Hence, the average pie mix does not exceed 31.5.
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