Question

According to a survey in a​ country, 39 ​% of adults do not own a credit...

According to a survey in a​ country, 39 ​% of adults do not own a credit card. Suppose a simple random sample of 200 adults is obtained. Complete parts​ (a) through​ (d) below.

(a) Describe the sampling distribution p the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below.

Determine the mean of the sampling distribution of

Determine the standard deviation of the sampling distribution of

(b) What is the probability that in a random sample of 200 ​adults, more than 42​% do not own a credit​ card?

Interpret this probability.

(c) What is the probability that in a random sample of 200 adults, between 37​% and 42​% do not own a credit​ card?

d) Would it be unusual for a random sample of 200 adults to result in 74 or fewer who do not own a credit​ card? Why?

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
According to a survey in a​ country, 39​% of adults do not own a credit card....
According to a survey in a​ country, 39​% of adults do not own a credit card. Suppose a simple random sample of 300 adults is obtained. Complete parts​ (a) through​ (d) below. ​(a) Describe the sampling distribution of ModifyingAbove p with caret​, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caret below. A. Not normal because n less than or...
According to a survey in a​ country, 23​% of adults do not own a credit card....
According to a survey in a​ country, 23​% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. Complete parts​ (a) through​ (d) below. a) Describe the sampling distribution of ModifyingAbove p with caretp​, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caretp below. A. Approximately normal because n less than or...
According to a survey in a​ country, 27​% of adults do not own a credit card....
According to a survey in a​ country, 27​% of adults do not own a credit card. Suppose a simple random sample of 500 adults is obtained. Complete parts​ (a) through​ (d) below. ​(a) Describe the sampling distribution of ModifyingAbove p with caretp​, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caretp below. A.Approximately normal because n less than or equals...
According to a survey in a​ country, 2727​% of adults do not own a credit card....
According to a survey in a​ country, 2727​% of adults do not own a credit card. Suppose a simple random sample of 900900 adults is obtained. Complete parts​ (a) through​ (d) below. ​(a) Describe the sampling distribution of ModifyingAbove p with caretp​, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caretp below. A. Approximately normal because n less than or...
According to a survey in a​ country, 24​% of adults do not own a credit card....
According to a survey in a​ country, 24​% of adults do not own a credit card. Suppose a simple random sample of 400 adults is obtained. Complete parts​ (a) through​ (d) below. b) what is the probability that in a random sample of 400 adults, more than 28% do not own a credit card? Interpret this probability: If 100 different random samples of 400 adults were​ obtained, one would expect ___ to result in more than 28​% not owning a...
According to a survey in a​ country, 3636​% of adults do not own a credit card....
According to a survey in a​ country, 3636​% of adults do not own a credit card. Suppose a simple random sample of 400400 adults is obtained. -Would it be unusual for a random sample of 400 adults to result in 136 or fewer who do not own a credit​ card? Why? Select the correct choice below and fill in the answer box to complete your choice. (Round to four decimal places as​ needed.) a) The result is unusual because the...
According to a survey in a​ country, 22​% of adults do not own a credit card....
According to a survey in a​ country, 22​% of adults do not own a credit card. Suppose a simple random sample of 300 adults is obtained a) What is the probability that in a random sample of 300 adults, between 19​% and 24​% do not own a credit​ card? The probability is ____. (Round to four decimal places as​ needed.) b) If 100 different random samples of 300 adults were​ obtained, one would expect nothing to result in between 19%...
About 29% of adults do not own a credit card. Suppose a random sample of 200...
About 29% of adults do not own a credit card. Suppose a random sample of 200 adults is asked, "Do you own a credit card?". a) describe the sampling distribution of phat of adults who own a credit card. b) Find the probability of the sample proportion greater than 0.35. c) Find the sample proportions with the middle 93.5%.
According to a survey in a country, 47​% of adults do not have any credit cards....
According to a survey in a country, 47​% of adults do not have any credit cards. Suppose a simple random sample of 400 adults is obtained. What is the probability that 195 or more have no credit cards?
According to a study conducted in one city, 29% of adults in the city have credit...
According to a study conducted in one city, 29% of adults in the city have credit card debts of more than $2000. A simple random sample of n=100 adults is obtained from the city. Describe the sampling distribution of p , the sample proportion of adults who have credit card debts of more than $2000. Select one: a. Approximately normal; μp = 0.29, σp = 0.0021 b. Exactly normal; μp = 0.29, σp = 0.045 c. Binomial; μp = 29,...