You must estimate the mean temperature (in degrees Fahrenheit) with the following sample temperatures:
55 |
41.4 |
45.5 |
38.3 |
45.3 |
42.7 |
34.6 |
50 |
25.5 |
48.7 |
Find the 99% confidence interval. Enter your answer as an
open-interval (i.e., parentheses)
accurate to two decimal places (because the sample data are
reported accurate to one decimal place).
99% C.I. =
From the given sample data : n=10 , ,
The sample mean is ,
The sample standard deviation is ,
Now , ; From t-table
The 99% confidence interval is ,
Therefore , the 99% C.I. = (34.3,51.1)
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