Question

The null hypothesis is there will be no difference in the frequency of graduates who are...

The null hypothesis is there will be no difference in the frequency of graduates who are employed in residential treatment facilities, community agencies, and private practice. The researcher used a Chi-Square Goodness of Fit test to analyze the data.

The expected frequency for each category of employment is 33.3%. The raw data on frequencies is:

Residential Treatment Facility                        8

            Community Agency                          12

            Private Practice                                    10

The output of the analysis is below. The results are X2 (2, N = 30) = .80, p = .670.

Employment

Observed N Expected N Residual

Residual treatment facility

Community Agency

Private Practice

Total

8

12

10

30

10.0

10.0

10.0

-2.0

2.0

.0

Test Statistics

Employment

Chi-Square

df

Asymp. Sig.

.800a

2

.670

What type of study design is used? Please explain.

Does the study design accurately test the null hypothesis?

Is the correct statistical test used to analyze the data? Why? Why not?

Regardless of whether or not the correct statistical test was used, are the results statistically significant? Social science research uses a p-value of .05 to determine statistical significance.

Does the researcher reject or fail to reject the null hypothesis?.

What are the implications of the results for the study and the counseling field?

Homework Answers

Answer #1

a) The study design is Testing for Goodness of Fit, here we test the random variable the number of employed graduates in different groups whose probability density function is unknown. We have only frequencies data to test hence we perform Goodness of fit test.

b) No the study design actually tests whether the data comes from a given distribution or not.

c) it is t he correct statistical test used to analyze the data because it how the observed value is significantly different from the expected value.

d) From the given test results the test is not significant because p-value is more than alpha (0.05).

e) researcher fail to reject the null hypothesis.

f) Researcher concludes that there is no difference in the frequency of graduates who are employed in residential treatment facilities, community agencies, and private practice.

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