Question

Use the data set provided in the main page of the experience for this application. 1. Complete the full hypothesis testing procedure to determine if students at TCC watch more television than Americans in general. Use the fact that on average Americans watch 3 hours of television per day with a standard deviation of 1.5 hours per day. Include the following in your report: a) Hypotheses using correct notation (2 points) b) type of test (left, right, two-tailed) (1 point), distribution used (normal or t) (1 point), reasons why (2 points) c) level of significance, choose one based on how serious the study is (2 points) d) Sample statistics (sample size and sample mean or sample proportion) (2 points) e) P-Value (2 point) (Round answer to four decimal places) f) Interpretation of P-value (Use Definition of P-Value but be specific to this context) (1 point) g) Graph of the sampling distribution with the are corresponding to the P-value shaded. (2 points) h) Decision (2 point) i) Conclusion in complete sentences. (3 points)

Average amount of TV watched per day (hours) 1, 5, 3.5, 4, 3, 4, 12, 2.4, 4, 5, 0.25, 1, 1.5, 2, 1.5, 1, 3, 7, 2, 2, 6, 3, 1, 3, 3, 4, 3.5, 3, 1.5, 4, 1, 0.2, 5, 0, 0.08, 2, 0, 2, 5, 3, 0.25, 3, 4, 2.5, 5

Answer 1

we consider the level of signficance as 0.05 or 5%
also
given that sd = 1.5 and
mu = 3

we calculate x bar as

now we know that the zstat is given as

as we are interested in the "watch more television than Americans in general" hence it is a right tail test

= (xbar-mu)/(sd/sqrt(n)) putting the values

(2.89-3)/(1.5/sqrt(45)) = -0.4919

now we check the z table for the p value as

P ( Z>?0.4919 )=P ( Z<0.4919 )=0.6879

hence we fail to reject the null hypothesis

The probability that Z>?0.4919 is equal to the blue area under the curve.