Karen wants to advertise how many chocolate chips (in grams) are in each Big Chip cookie at her bakery. She randomly selects a sample of 10 cookies and finds that the number of chocolate chips per cookie in the sample has a mean of 58.7 and a standard deviation of 41.2. What is the 90% confidence interval for the number of chocolate chips per cookie for Big Chip cookies?
Solution :
Given that,
t /2,df = 1.833
Margin of error = E = t/2,df * (s /n)
= 1.833 * (41.2 / 10)
Margin of error = E = 23.9
The 90% confidence interval estimate of the population mean is,
- E < < + E
58.7 - 23.9 < < 58.7 + 23.9
34.8 < < 82.6
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