If, in a sample of nequals16 selected from a normal population, Upper X overbar equals 60 and Upper S equals 20, what is your statistical decision if the level of significance, alpha, is 0.01, the null hypothesis, Upper H 0, is mu equals 50 comma and the alternative hypothesis, Upper H 1 comma is mu not equals 50 question mark Click here to view page 1 of the table of the critical values of t. LOADING... Click here to view page 2 of the table of the critical values of t. LOADING... Determine the critical value(s). The critical value(s) is(are) 0.05 nothing. (Round to four decimal places as needed. Use a comma to separate answers as needed.)
n = Sample Size = 16
= Sample Mean = 60
s = Sample SD = 20
= Significance level = 0.01
H0: Null Hypothesis: = 50
H1: Alternative Hypothesis: 50
Degrees of Freedom = n - 1 = 16 - 1 = 15
From Table, critical values of t = 2.9467
So,
Answer is:
The critical values are:
- 2.9467, 2.9467
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