Use the Student's t distribution to find tc for a 0.90 confidence level when the sample is 6. (Round your answer to three decimal places.)
confidence level (c) = 0.90
= (1-c) = (1-0.90) = 0.10
sample size (n) = 6
degrees of freedom = (n-1 )= (6-1) = 5
t critical value for 0.90 confidence level , both tailed test be:-
[ using t distribution table for df= 5, alpha= 0.10,both tailed test....or in any blank cell of excel type =T.INV.2T(0.1,5) ]
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