11.4 #7
Let x be a random variable that represents the batting average of a professional baseball player. Let y be a random variable that represents the percentage of strikeouts of a professional baseball player. A random sample of n = 6 professional baseball players gave the following information.
x | 0.328 | 0.270 | 0.340 | 0.248 | 0.367 | 0.269 |
y | 3.2 | 7.8 | 4.0 | 8.6 | 3.1 | 11.1 |
(a) Find ?x, ?y, ?x2, ?y2, ?xy, and r. (Round r to three decimal places.)
?x = | |
?y = | |
?x2 = | |
?y2 = | |
?xy = | |
r = |
(b) Use a 5% level of significance to test the claim that
? ? 0. (Round your answers to two decimal places.)
t = | |
critical t = |
Conclusion
Reject the null hypothesis, there is sufficient evidence that ? differs from 0.Reject the null hypothesis, there is insufficient evidence that ? differs from 0. Fail to reject the null hypothesis, there is insufficient evidence that ? differs from 0.Fail to reject the null hypothesis, there is sufficient evidence that ? differs from 0.
(c) Find Se, a, and b. (Round
your answers to four decimal places.)
Se = | |
a = | |
b = |
(d) Find the predicted percentage ? of strikeouts for a
player with an x = 0.34 batting average. (Round your
answer to two decimal places.)
%
(e) Find an 80% confidence interval for y when x
= 0.34. (Round your answers to two decimal places.)
lower limit | % |
upper limit | % |
(f) Use a 5% level of significance to test the claim that
? ? 0. (Round your answers to two decimal places.)
t = | |
critical t = |
Conclusion
Reject the null hypothesis, there is sufficient evidence that ? differs from 0.Reject the null hypothesis, there is insufficient evidence that ? differs from 0. Fail to reject the null hypothesis, there is insufficient evidence that ? differs from 0.Fail to reject the null hypothesis, there is sufficient evidence that ? differs from 0.
Hello.
I'm using excel to solve your question. If you want it solved in any other way, let me know in the comments and I'll suggest you to post a new question for (e) and (f) parts specifically mentioning to attempt only those parts.
(a)
(b)
, df = n - 2
Critcal t,
df = n - 2 = 4,
(c) Using Data -> Data Analysis -> Regression
Hence, SE = 1.7145, a = 25.1927, b = -62.2153
(d)
I hope this solves your doubt.
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