If you want to be 95% confident that estimating the population mean is within a sampling error of + -200 and the standard deviation is assumed to be 1000, what is the sample size required? Round up the answer to the nearest integer.
Solution
standard deviation = =1000
Margin of error = E = +/- 200
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
sample size = n = [Z/2* / E] 2
n = ( 1.96* 1000 /200 )2
n =96.04
Sample size = n =96
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