Question
A sample of 45 pro football players had an average height of 6.179ft with a sample...
A sample of 45 pro football players had an average height of 6.179ft with a sample standard deviation of 0.366ft and a sample of 40 pro basketball players had a mean height of 6.453ft with a sample standard deviation of 0.314ft. If mu1 is the mean height for all football players and mu2 is the mean height of all basketball players, find a 90% confidence interval for mu1 - mu2. Interpret the confidence interval in the context of the problem.
Homework Answers
Answer #1
Not the answer you're looking for?
Similar Questions
Suppose a random sample of 50 basketball players have an average height of 78 inches. Also...
Suppose a random sample of 50 basketball players have an
average height of 78 inches. Also assume that the population
standard deviation is 1.5 inches.
a) Find a 99% confidence interval for the population
mean height.
b) Find a 95% confidence interval for the population
mean height.
c) Find a 90% confidence interval for the population
mean height.
d) Find an 80% confidence interval for the population
mean height.
e) What do you notice about the length of the confidence...
Independent random samples of professional football and basketball players gave the following information. Assume that the...
Independent random samples of professional football and
basketball players gave the following information. Assume that the
weight distributions are mound-shaped and symmetric.
Weights (in lb) of pro football players: x1; n1 = 21 246 261 255
251 244 276 240 265 257 252 282 256 250 264 270 275 245 275 253 265
271
Weights (in lb) of pro basketball players: x2; n2 = 19 203 200
220 210 192 215 223 216 228 207 225 208 195 191 207...
Independent random samples of professional football and basketball players gave the following information. Assume that the...
Independent random samples of professional football and
basketball players gave the following information. Assume that the
weight distributions are mound-shaped and symmetric.
Weights (in lb) of pro football players:
x1; n1 = 21
248
262
255
251
244
276
240
265
257
252
282
256
250
264
270
275
245
275
253
265
272
Weights (in lb) of pro basketball players:
x2; n2 = 19
202
200
220
210
193
215
223
216
228
207
225
208
195
191
207...
Independent random samples of professional football and basketball players gave the following information. Assume that the...
Independent random samples of professional football and
basketball players gave the following information. Assume that the
weight distributions are mound-shaped and symmetric.
Weights (in lb) of pro football players:
x1; n1 = 21
245
262
254
251
244
276
240
265
257
252
282
256
250
264
270
275
245
275
253
265
271
Weights (in lb) of pro basketball players:
x2; n2 = 19
202
200
220
210
192
215
223
216
228
207
225
208
195
191
207...
Independent random samples of professional football and basketball players gave the following information. Assume that the...
Independent random samples of professional football and
basketball players gave the following information. Assume that the
weight distributions are mound-shaped and symmetric.
Weights (in lb) of pro football players:
x1; n1 = 21
245
263
256
251
244
276
240
265
257
252
282
256
250
264
270
275
245
275
253
265
271
Weights (in lb) of pro basketball players:
x2; n2 = 19
202
200
220
210
193
215
223
216
228
207
225
208
195
191
207...
Independent random samples of professional football and basketball players gave the following information. Assume that the...
Independent random samples of professional football and
basketball players gave the following information. Assume that the
weight distributions are mound-shaped and symmetric.
Weights (in lb) of pro football players:
x1; n1 = 21
248
263
256
251
244
276
240
265
257
252
282
256
250
264
270
275
245
275
253
265
271
Weights (in lb) of pro basketball players:
x2; n2 = 19
204
200
220
210
192
215
223
216
228
207
225
208
195
191
207...
3. For a group of 22 college football players, the mean heart rate after a morning...
3. For a group of 22 college football players, the mean heart
rate after a morning workout session was 86 beats per minute, and
the standard deviation was 5. Find and interpret the 90% confidence
interval of the true mean for all college football players after a
workout session.
The population standard deviation for the height of college football players is 3.3 inches. If we...
The population standard deviation for the height of college
football players is 3.3 inches. If we want to estimate a 90%
confidence interval for the population mean height of these players
with a 0.7 margin of error, how many randomly selected players must
be surveyed? (Round up your answer to nearest whole number)
Answer:
The average height of 12 randomly selected Muppet basketball players is 50 inches with a standard...
The average height of 12 randomly selected Muppet basketball
players is 50 inches with a standard deviation of 4 inches. The
average height of 15 randomly selected Muppet football players is
47 inches with a standard deviation of 3 inches. Assuming the
heights of both populations are normally distributed, are Muppet
basketball players taller than football players?
In a random sample of 100 basketball players, the average vertical jump was 38 inches. Suppose...
In a random sample of 100 basketball players, the average
vertical jump was 38 inches. Suppose the standard deviation for all
basketball players’ vertical jumps is 10 inches.
a. Determine a 95% confidence interval for the average
vertical jump and determine the margin of error.
b. Interpret your result.
c. If you want a margin of error of only 1 inch in the 95%
confidence interval, determine the number of basketball players you
would need to sample. show all work
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 2 minutes ago
asked 13 minutes ago
asked 15 minutes ago
asked 21 minutes ago
asked 25 minutes ago
asked 29 minutes ago
asked 53 minutes ago
asked 58 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 2 hours ago