Question

A study in 2007 involved 118 college students who volunteered to fill out a survey in...

A study in 2007 involved 118 college students who volunteered to fill out a survey in exchange for $5. After completing the survey, the students were asked if they would like to donate any of their $5 participation fee to a real, legitimate charity that addressed global hunger. A randomization led to half of the students (group 1) being shown a picture and description of a young girl who had been helped by the charity, and the other half of the students (group 2) being given statistical information about the effectiveness of the charity (but nothing about any individual child and no pictures). The sociologists wanted to test whether there would be a stronger response to the plight of an individual, pictured child than to statistics about all the children. The data that was collected was the amount of money the college students each donated from their $5.

6) Write the null and alternate hypotheses about the mean amounts donated.

7) We have no idea if the population or sample data in this study are approximately symmetric. Why can we continue with t- distribution procedures?

8) The sample mean from group 1 was $2.12, and the sample standard deviation was $2.13. The sample mean from group 2 was $1.21, and the sample standard deviation was $1.67. What is the difference between the sample means?

9) Use 2-SampTInt to calculate a 90% confidence interval. Is there statistical evidence that the students gave more money whenpresented with an individual’s information rather than just being given general information? Why or why not? (Use the STATSoption. Choose No for Pooled.)

10) WITHOUT calculating it using a T-test, is the P-value less than 0.05? Why? (Use the results from the confidence interval as a guideline).

Homework Answers

Answer #1

Ans: There is statistical evidence that the students gave more money when presented with an individual’s information rather than just being given general information at 0.10 level of significance because the confidence interval does not include value zero.

10) WITHOUT calculating it using a T-test, is the P-value less than 0.05? Why? (Use the results from the confidence interval as a guideline).

Ans: Yes, the p-value is less than 0.05 because of the 90% confidence interval does not inlude zero.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a study of physical fitness, a random sample college students volunteered to exercise. Their exercise...
In a study of physical fitness, a random sample college students volunteered to exercise. Their exercise capacity times (in minutes) are given below. Answer the following questions. 13.0 21.0 13.5 35.0 20.5 27.0 28.0 28.0 23.0 13.0 53.0 51.0 Calculate a 99% CI for the population mean capacity time.
A survey of a group of students at a certain college, we call College ABC, asked:...
A survey of a group of students at a certain college, we call College ABC, asked: "About how many hours do you study in a week?" The mean response of the 400 students is 15.8 hours. Suppose that the study time distribution of the population is known to be normal with a standard deviation of 8.5 hours. Use the survey results to construct a 95% confidence interval for the mean study time at the College ABC. Show your work neatly.
Do college students who have volunteered for community service work differ from those who have not?...
Do college students who have volunteered for community service work differ from those who have not? A study obtained data from 57 students who had done service work and 18 who had not. Group Condition N X bar S 1 Service 57 104.12 14.60 2 No Service 18 97.82 14.20 Is there strong evidence (a=0.05 significance level) that students who have engaged in community service are on the average more attached to their friends. Please show all working.
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 40 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.97 hours. You want to construct a 99% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 45 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.86 hours. You want to construct a 99% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 45 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.97 hours. You want to construct a 99% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 50 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.97 hours. We want to construct a 95% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 45 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.97 hours. We want to construct a 95% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 45 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.97 hours. We want to construct a 95% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 40 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.86 hours. We want to construct a 99% confidence interval for the mean nightly hours of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT