Part of an ANOVA table is shown below.
Source of Variation |
Sum of |
Degrees |
Mean |
F |
Between Treatments |
64 |
8 |
||
Within Treatments (Error) |
2 |
|||
Total |
100 |
If we want to determine whether or not the means of the populations are equal, the p-value is
a. |
greater than .1. |
|
b. |
between .05 to .1. |
|
c. |
between .025 to .05. |
|
d. |
less than .01. |
Source of | Sum of | Degrees | Mean | F |
Variation | Squares | of Freedom | Square | |
Between Treatments | 64 | 4 | 16 | 8 |
Within Treatments (Error) | 36 | 18 | 2 | |
Total | 100 |
Sum of squares of errors = Total sum of squares - Sum of squares between treatments = 100-64 =36
Degrees of freedom of errors = Sum of squares of errors / Mean square errors
= 36/2 = 18
Mean square between treatments = Mean square errors * F = 2*8 = 16
Degrees of freedom between treatments = Sum of squares between treatments / Mean square between treatments
= 64/16 = 4
p-value (Using excel function) = =F.DIST(x,deg_1,deg_2,cumulative) =F.DIST(8,4,18,FALSE) = 0.0005 (less than 0.01) Option d
Get Answers For Free
Most questions answered within 1 hours.