Question
The body temperatures of adults are normally distributed with a mean of 98.6 degrees and a...
The body temperatures of adults are normally distributed with a mean of 98.6 degrees and a standard deviation of 0.71 degrees. What temperature represents the 97th percentile? Round to the nearest hundredth.
Homework Answers
Answer #1
=> P97 = 1.3419 + 98.6 = 99.9419 =
99.94 ( round to hundredth)
Hence, 99.94 degree represent 97th percentile.
Not the answer you're looking for?
Similar Questions
The body temperatures of adults are normally distributed with a mean of 98.6 degrees Fahrenheit and...
The body temperatures of adults are normally distributed with a
mean of 98.6 degrees Fahrenheit and a standard deviation of 1.2
degrees Fahrenheit. If 31 adults are randomly selected, find the
probability that their mean body temperature is greater than 99.3
degrees Fahrenheit.
The body temperatures of adults are normally distributed with a mean of 98.60˚F and a standard...
The body temperatures of adults are normally distributed with a
mean of 98.60˚F and a standard deviation of 0.73˚F.
A)What temperature would put you in the 76th percentile? Round
to 2 decimals
B)What temperature would put you in the bottom 20% of
temperatures? Round to 2 decimals.
C)What is the probability that someone has a body temperature of
100°F or more? [Remember to round probabilities to 4 decimal
places]
D)What is the probability that someone has a body temperature
less...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of
adults in one small town are:
96.6
99.6
97.8
99.2
97.4
98.6
98.8
Assume body temperatures of adults are normally distributed. Based
on this data, find the 95% confidence interval of the mean body
temperature of adults in the town. Enter your answer as an
open-interval (i.e., parentheses)
accurate to 1 decimal place. Assume the data is from a normally
distributed population.
95% C.I. =
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are:...
The body temperatures in degrees Fahrenheit of a sample of
adults in one small town are:
97.8
96.6
98.7
98.6
99.3
98.3
99.4
99.8
96.3
99.9
96.9
Assume body temperatures of adults are normally distributed. Based
on this data, find the 95% confidence interval of the mean body
temperature of adults in the town. Enter your answer as an
open-interval (i.e., parentheses)
accurate to 3 decimal places. Assume the data is from a normally
distributed population.
95% C.I. = ____
Assume that the population of human body temperatures has a mean of 98.6 degrees F, as...
Assume that the population of human body temperatures has a
mean of 98.6 degrees F, as is commonly believed. Also assume that
the population has a standard deviation of 0.62 degrees F.
If a sample size of n=106 is randomly selected, find the
probability of getting a mean of 98.2 degrees F or lower. (Verify
that the central limit theorem applies if you are using it.)
A study was done with this sample size of 106 randomly selected
adults and...
The body temperatures in degrees Fahrenheit of a sample of 6 adults in one small town...
The body temperatures in degrees Fahrenheit of a sample of 6
adults in one small town are:
97.9
99.6
98.6
98.5
99.5
97.7
Assume body temperatures of adults are normally distributed. Based
on this data, find the 98% confidence interval of the mean body
temperature of adults in the town. Enter your answer as an
open-interval (i.e., parentheses)
accurate to twp decimal places (because the sample data are
reported accurate to one decimal place).
98% C.I. =
Answer should be...
It is generally accepted that the mean body temperature is 98.6 degrees. If a sample of...
It is generally accepted that the mean body temperature is 98.6
degrees. If a sample of size 100 resulted in a sample mean of 98.3
degrees with a standard deviation of 0.64 degrees. Does this sample
suggest that the mean body temperature is actually lower than 98.6
degrees?
Body Temperatures: Most people think that the "normal" adult body temperature is 98.6 degrees Fahrenheit. That...
Body Temperatures: Most people think that the "normal" adult
body temperature is 98.6 degrees Fahrenheit. That figure, based on
a 19th century study, has recently been challenged. A more recent
figure is 98.1 degrees. The standard deviation appears to be around
0.6 degrees and the distribution is approximately Normal. A) Based
on this model, below what body temperature are the coolest 15% of
all people? degrees (Round your answer to 1 decimal place) B) Based
on this model, above what...
The body temperatures in degrees Fahrenheit of a sample of 9 adults in one small town...
The body temperatures in degrees Fahrenheit of a sample of 9
adults in one small town are:
97.9
97.6
96.3
98.3
98.7
98
96.7
98.6
97.3
Assume body temperatures of adults are normally distributed. Based
on this data, find the 90% confidence interval of the mean body
temperature of adults in the town. Enter your answer as an
open-interval (i.e., parentheses)
accurate to twp decimal places (because the sample data are
reported accurate to one decimal place).
90% C.I. =...
Assume that human body temperatures are normally distributed with a mean of 98.19 degrees Upper F...
Assume that human body temperatures are normally distributed
with a mean of 98.19 degrees Upper F and a standard deviation of
0.64 degrees Upper F.
a. A hospital uses 100.6 degrees Upper F as the lowest
temperature considered to be a fever. What percentage of normal and
healthy persons would be considered to have a fever? Does this
percentage suggest that a cutoff of 100.6 degrees Upper F is
appropriate?
b. Physicians want to select a minimum temperature for requiring...
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 2 minutes ago
asked 6 minutes ago
asked 6 minutes ago
asked 7 minutes ago
asked 26 minutes ago
asked 27 minutes ago
asked 44 minutes ago
asked 48 minutes ago
asked 51 minutes ago
asked 53 minutes ago
asked 1 hour ago
asked 1 hour ago