Question

Use the margin of error of 4, confidence interval of 90% and ?=28 to find the...

Use the margin of error of 4, confidence interval of 90% and ?=28 to find the minimum sample size required to estimate an unknown population mean ?. (If using TI-84 plus, show steps)

Homework Answers

Answer #1

We have given here,                  
                  
Population standard deviation =   28  
Margin of error =E=4  
Level of significance =   1-0.90=0.1  
Z critical value is (by using Z table)=1.645  
Sample size formula is                   


=132.6

Sample size
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
3. Use the margin of error of 4, confidence interval of 90% and ?=28 to find...
3. Use the margin of error of 4, confidence interval of 90% and ?=28 to find the minimum sample size required to estimate an unknown population mean ?.
Find the margin of error for a​ 95% confidence interval for estimating the population mean when...
Find the margin of error for a​ 95% confidence interval for estimating the population mean when the sample standard deviation equals 90 with a sample size of​ (i) 484 and​ (ii) 1600 ​(i) Find the margin of error for a​ 95% confidence interval for estimating the population mean when the sample standard deviation equals 90 with a sample size of 484 (ii). ​(ii) Find the margin of error for a​ 95% confidence interval for estimating the population mean when the...
Compute E, the margin of error for the t interval, for a 90% confidence interval for...
Compute E, the margin of error for the t interval, for a 90% confidence interval for m if a random sample of size n = 40 with sample standard deviation s = 2.8 is drawn from a population with s unknown.
4. Find the margin of error E. In a random sample of 151 college students, 84...
4. Find the margin of error E. In a random sample of 151 college students, 84 had part-time jobs. Find the margin of error E for the 95% confidence interval used to estimate the population proportion. Round your answer to four decimal places. Answer 0.0792 5. Find the minimum sample size required to estimate the population proportion p: Margin of error: 0.10; confidence level: 95%; from a prior study, is known to be 66%. 6. Find the minimum sample size...
1) Use the given confidence interval to find the margin of error and the sample mean....
1) Use the given confidence interval to find the margin of error and the sample mean. ​(12.8​,19.8​) 2) In a random sample of four microwave​ ovens, the mean repair cost was ​$60.00 and the standard deviation was ​$12.00. Assume the population is normally distributed and use a​ t-distribution to construct a 99​% confidence interval for the population mean ?. What is the margin of error of ? Interpret the results.
Determine the margin of error for a confidence interval to estimate the population proportion for the...
Determine the margin of error for a confidence interval to estimate the population proportion for the following confidence levels with a sample proportion equal to 0.35 and n= 120 the margin of error for a confidence interval to estimate the population portion for 90% confidence level is the margin of error for a confidence interval to estimate the population portion for 95% confidence level is the margin of error for a confidence interval to estimate the population portion for 97%...
Use the confidence interval, (36.482, 41.352), to answer the questions. What is the margin of error,...
Use the confidence interval, (36.482, 41.352), to answer the questions. What is the margin of error, E? What is the sample mean, x? Let c = 0.99, σ = 3.7, and E = 2.2. What is the minimum sample size, n, needed to estimate μ
Use the Confidence Interval to find the Margin of Error and the Sample mean: 1) (45.67,...
Use the Confidence Interval to find the Margin of Error and the Sample mean: 1) (45.67, 57.82) Margin of Error =  , Sample mean = 2) (12.05,12.23) Margin of Error =  , Sample mean = Do not round your answers.
(1 point) Working backwards, Part I. A 90% confidence interval for a population mean is (44,...
(1 point) Working backwards, Part I. A 90% confidence interval for a population mean is (44, 50). The population distribution is approximately normal and the population standard deviation is unknown. This confidence interval is based on a simple random sample of 28 observations. Calculate the sample mean, the margin of error, and the sample standard deviation. Use the t distribution in any calculations. Round non-integer results to 4 decimal places. Sample mean = Margin of error = Sample standard deviation...
Use the t-distribution to find a confidence interval for a mean μ given the relevant sample...
Use the t-distribution to find a confidence interval for a mean μ given the relevant sample results. Give the best point estimate for μ, the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed. A 90% confidence interval for μ using the sample results x¯=3.5, s=0.4, and n=100 Round your answer for the point estimate to one decimal place, and your answers for the margin of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT