Recent test scores on the Law School Admission Test (LSAT) are normally distributed with a mean of 162.4 and a standard deviation of 15.9. What is the probability that the mean of 12 randomly selected scores is less than 161?
0.535 |
0.620 |
0.380 |
0.465 |
Solution :
Given that ,
mean = = 162.4
standard deviation = = 15.9
n = 12
= 101 and
= / n = 15.9 / 12
P( < 161) = P(( - ) / < (161 - 162.4) / 15.9 / 12 ) = P(z < -0.305)
Using standard normal table,
P( < 161) = 0.380
Probability = 0.380
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