the cholesterol levels of an adult can be described by a normal model with a mean of 199 mg/dL and a standard deviation of 28.
what's the IQR
Solution:-
Given that,
mean = = 199
standard deviation = = 28
Using standard normal table,
The z dist'n First quartile is,
P(Z < z) = 25%
= P(Z < z) = 0.25
= P(Z < -0.6745 ) = 0.25
z = -0.6745
Using z-score formula,
x = z * +
x = -0.6745 * 28 + 199
x = 180.11
First quartile =Q1 = 180.11
The z dist'n Third quartile is,
P(Z < z) = 75%
= P(Z < z) = 0.75
= P(Z < 0.6745 ) = 0.75
z = 0.6745
Using z-score formula,
x = z * +
x = 0.6745 * 28 + 199
x = 217.89
Third quartile =Q3 = 217.89
IQR = Q3 - Q1
IQR = 217.89 - 180.11
IQR = 37.78
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