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Question 61 pts There are two types of sneetches, the star-bellied sneetch (S. astra) and the...

Question 61 pts

There are two types of sneetches, the star-bellied sneetch (S. astra) and the plain sneetch (S. simplex). Professor O. B. Servant counted sightings of these sneetches, identified each sneetch he saw, and classified their location into the three types: Ground, Tree, and Lake. The number of sightings are shown in the table below:

S. astra S. simplex
Ground 60 35
Tree 34 41
Lake 28 42

Professor O.B. Servant would like to know if the habitat use is independent of the types of sneetches.

Find the expected frequency for S. astra on ground if the habitat use is independent of the types.

Round your answer to the nearest 0.01.

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Question 71 pts

Continue the previous problem.

Calculate the test statistic X2 for testing the independence of the two variables.

Round your answer to the nearest 0.01.

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Question 81 pts

Continue the previous problem.

Find the number of degrees of freedom for the test statistic X2 for testing the independence of the two variables.

Round your answer to the nearest 0.01.

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Question 91 pts

Continue the previous problem.

Find the p-value for testing the independence of the two variables.

Round your answer to the nearest 0.01.

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Question 101 pts

Continue the previous problem.

Based on the p-value, is the habitat use independent of type?

Cannot tell.
Yes
No

Homework Answers

Answer #1

61)xpected frequency for S. astra on ground =row total*column total/grand total=48.29

71)

applying chi square test:

Expected Ei=?row*?column/?total S. Astra S.Simplex Total
Ground 48.2917 46.708 95
tree 38.125 36.875 75
lake 35.583 34.417 70
Total 122 118 240
chi square =(Oi-Ei)2/Ei S. Astra S.Simplex Total
Ground 2.839 2.935 5.774
tree 0.446 0.461 0.908
lake 1.616 1.671 3.287
Total 4.901 5.067 9.968

test statistic X2 =9.97

81_)

number of degrees of freedom =(row-1)*(column-1)=(3-1)*(2-1)=2

91)

p value =0.01

101)

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