If a population distribution has a mean of 70 and a standard deviation of 17, what is the percentile for a sample mean of 75 with a sample size of 70? Report your answer to the fourth decimal place and in proportion form (not in percentages).
Solution:
Given that,
mean = = 70
standard deviation = = 17
Sample size = n = 70
So,
= 70
= ( /n) = (17 / 70 ) = 2.0319
p ( < 75 )
= p ( - /) < (75 - 70 / 2.0319)
= p ( z < 5 / 2.0319)
= p ( z < 2.46 )
Using z table
= 0.9931
Proportion = 0.9931
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