Question

Bill needs to schedule a meeting for tomorrow afternoon, but he also has a tee time for golf at 10:00 a.m. Bill usually finishes a round of golf in 4.45 hours. If the course is empty and he doesn’t spend too much time looking for lost balls, he can finish in 3.45 hours. However, if the course is crowded, there are rain delays, and/or he hits many bad shots, a round can take as much as 5.70 hours.

a. What is the expected time that Bill will require to complete his round of golf tomorrow?(Round your answer to 2 decimal places.)

Got 4.49

b. If Bill schedules a meeting to begin at 03:30 p.m. tomorrow and it takes 30 minutes for him to get from the golf course to his office, what is the probability that he will make it to the meeting on time?(Do not round intermediate calculations. Round your answer to the nearest whole percent.)

I got 1 percent? but it is incorrect can anyone help!

Answer 1

Answer:

a)

Given

m = 4.45 hours

b = 5.70 hours

a = 3.45 hours

Expected time = (a + 4m + b) / 6

substitute values

= (3.45 + 4*4.45 + 5.70) / 6

= 26.95 / 6

= 4.4917 hours

= 4.4917*60 min

= 269.5 min

= 4 hours 29.5 min

b)

To give the probability that he will make it to the meeting on time

Consider,

Standard deviation of time() = (b - a) / 6

substitute values

= (5.70 - 3.45) / 6

= 2.25/6

= 0.375 hours

= 0.375*60 min

= 22.5 minutes

Meeting time = 3.30 pm

Let us consider 30 minutes for travel,

target time = 3:30 - 10:00 - 00:30

= 5 hours

now consider,

Z = (Target completion time - mean completion time)/

substitute the values

= (5 - 4.49) / 0.375

= 0.51 / 0.375

= 1.36

P(Z < 1.36) = 0.9131 [since from z table]

Hence the probability that he will make it to the meeting on time is 91%