Question

If n=31, ¯ x (x-bar)=33, and s=3, find the margin of error at a 90% confidence level Give your answer to two decimal places.

Answer #1

Solution :

Given that,

Point estimate = sample mean = = 33

sample standard deviation = s = 3

sample size = n = 31

Degrees of freedom = df = n - 1 = 30

At 90% confidence level the t is ,

t_{
/2,df} = t_{0.05,24} = 1.697

Margin of error = E = t_{/2,df}
* (s /n)

= 1.697 * ( 3/ 31)

= 0.91

The Margin of error is 0.91

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