Question

A study by the Fellows Research Group evaluated the mental health status of 150 women in the inner city of Philadelphia. The results of the study are in an Excel file in the Week 2 assignment area and in the “Course Resources” area. Load the data set into StatCrunch and perform a one sample t test on the mental health score given that the national average on this test is 45. Is the result significant? Copy and paste your StatCrunch output into your submission document for full credit.

   Observe the statcrunch video for one sample t test

Hints: do you have two independent (unrelated) groups? Also, confirm that your DV is interval or ratio; you cannot have a nominal DV. You cannot have three groups (three groups require ANOVA).

The IV is_____?     The DV is _______?

One sample T hypothesis test:

μ : Mean of variable
H₀ : μ = 45
H_A : μ ≠ 45

Hypothesis test results:

Variable	Sample Mean	Std. Err.	DF	T-Stat	P-value
MentalHlth	45.88	0.89021125	149	0.98852941	0.3245

id	MentalHlth	Marital	FeltDown	GPCOG
180001	54	Married	None of the time	14
180002	55	Married	Some of the time	5
180003	51	Divorced	Some of the time	12
180004	52	Never married	Some of the time	7
180005	49	Never married	Some of the time	9
180006	54	Married	Little of the time	15

Answer 1

Dependent variable must be a ratio or interval, so the dependent variable is mental health because it is dependent on the marital status and feltdown variable

So,DV = mental health

Independent variable be categorical because independent variables are not dependent on any other variable. So, independent variables are marital status and Feltdown

therefore, IV = marital status and Feltdown

Using the given output data table

test statistic t is 0.988 with p value = 0.3245

So, p value is greater than 0.05 significance level, fail to reject the null hypothesis

So, result is insignificant at 0.05 level of significance