In a random sample of 27 people, the mean commute time to work was 33.3 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval for the population mean mu. What is the margin of error of mu? Interpret the results.
The confidence interval for the population mean μ
(Round to one decimal place as needed.)
The margin of error of μ
Round to one decimal place as needed.)
Int(erpret the results.
A.It can be said that
8080%
of people have a commute time between the bounds of the confidence interval.
B.With
8080%
confidence, it can be said that the commute time is between the bounds of the confidence interval.
C.If a large sample of people are taken approximately
8080%
of them will have commute times between the bounds of the confidence interval.
D.With
8080%
confidence, it can be said that the population mean commute time is between the bounds of the confidence interval.
a)
t critical value at 0.20 significance level with 26 df = 1.315
80% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
33.3 - 1.315 * 7.3 / sqrt(27) < < 33.3 + 1.315 * 7.3 / sqrt(27)
31.5 < < 35.1
80% CI is ( 31.5 , 35.1 )
b)
Margin of error = t * S / sqrt(n)
= 1.315 * 7.3 / sqrt(27)
= 1.8
c)
Interpretation -
With 80% confidence it can be said that the population mean commute time is between the bounds of the
confidence interval.
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