Question

The mean incubation time of fertilized eggs is 21 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 day.

(a) Determine the 20th percentile for incubation times.

(b) Determine the incubation times that make up the middle 39%.

Answer #1

solution:

Given that,

mean = = 21

standard deviation = = 1

Using standard normal table,

P(Z < z) = 20%

= P(Z < z) = 0.20

z = -0.84 Using standard normal table,

Using z-score formula

x= z * +

x= -0.84*1+21

x= 20.16

b.

middle 39% of score is

P(-z < Z < z) = 0.39

P(Z < z) - P(Z < -z) = 0.39

2 P(Z < z) - 1 = 0.39

2 P(Z < z) = 1 + 0.39 = 1.39

P(Z < z) = 1.39/ 2 = 0.695

P(Z <0.51 ) = 0.695

z ± 0.51 using z table

Using z-score formula

x=± z * +

x= ±0.51*1+21

x= 20.49 , 21.51

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Chapter 7.2 Question 14
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dayday.
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Click here to view graph d.
LOADING...
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