The life of a machine is normally distributed with a standard deviation of 35 hours. A quality assurance officer takes a sample of 60 machines randomly from a batch containing 5000 machines. The average life of this sample is between 1385.45 and 1405.62 hours.
a) Find a 90% confidence interval to estimate the average life of machines in this lot.
Solution:
From given information,
Population standard deviation = 35
Sample size = n = 60
We have to find sample mean from given range.
Sample mean = = 1385.45 + 1405.62 / 2
Sample mean = = 1395.53
Hence 90% confidence interval is , ( 1388.098 , 1402.962 )
Done
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