M&M plain candies come in various colors. According to the M&M/Mars Department of Consumer Affairs, the distribution of colors for plain M&M candies is as follows.
Color | Purple | Yellow | Red | Orange | Green | Blue | Brown |
Percentage | 17% | 18% | 17% | 9% | 8% | 10% | 21% |
Suppose you have a large bag of plain M&M candies and you
choose one candy at random.(a) Find P(green candy
or blue candy).
Are these outcomes mutually exclusive? Why?
Yes. Choosing a green and blue M&M is not possible.Yes. Choosing a green and blue M&M is possible. No. Choosing a green and blue M&M is not possible.No. Choosing a green and blue M&M is possible.
(b) Find P(yellow candy or red candy).
Are these outcomes mutually exclusive? Why?
Yes. Choosing a yellow and red M&M is possible.No. Choosing a yellow and red M&M is not possible. No. Choosing a yellow and red M&M is possible.Yes. Choosing a yellow and red M&M is not possible.
(c) Find P(not purple candy).
Color | Purple | Yellow | Red | Orange | Green | Blue | Brown |
Percentage | 17% | 18% | 17% | 9% | 8% | 10% | 21% |
a.) When one candy is chosen at random:
P(green candy or blue candy) = P(green candy) + P(blue candy) = 0.08 + 0.1 = 0.18
Yes. Choosing a green and blue M&M is not possible. Candy can be of any one color, green or blue or any other.
b.) When one candy is chosen at random:
P(yellow candy or red candy) = P(yellow candy) + P(red candy) = 0.18 + 0.17 = 0.35
Yes. Choosing a yellow and red M&M is not possible.Candy can be of any one color, yellow or red or any other.
c.) P(not purple candy) = 1 - P(purple candy) = 1 - 0.17 = 0.83
Get Answers For Free
Most questions answered within 1 hours.