A study at Harvard found that 44% of their students binge drink. You are at Princeton doing a similar study. How many people do you need to interview to get your interval width down to 10 percentage points? For a 95% CI, what is that sample size?
Solution:
Given that,
= 0.44
1 - = 1 - 0.44 = 0.56
margin of error = E =10% = 0.10 / 2 = 0.05
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Sample size = n = ((Z / 2) / E)2 * * (1 - )
= (1.960 / 0.05 )2 * 0.44 * 0.56
= 378.628
= 379
n = sample size = 379
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