Question

A particular fruit's weights are normally distributed, with a
mean of 741 grams and a standard deviation of 32 grams.

The heaviest 9% of fruits weigh more than how many grams?

Give your answer to the nearest gram.

Answer #1

Solution:-

Given that,

mean = = 741

standard deviation = = 32

Using standard normal table,

P(Z > z) = 9%

= 1 - P(Z < z) = 0.09

= P(Z < z) = 1 - 0.09

= P(Z < z ) = 0.91

= P(Z < 1.34 ) = 0.91

z = 1.34

Using z-score formula,

x = z * +

x = 1.34 * 32 + 741

x = 783.88

x = 784 grams

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