approximate the following binomial probabilities for
this continuous probability distribution
p(x=18,n=50,p=0.3)
p(x>15,n=50,p=0.3)
p(x>12,n=50,p=0.3)
p(12<x<18,n=50,p,=0.3)
From normal approximation of binomial distribution
np > 5 and np(1-p)>5 so that
mean =np = 15
a)
p(x=18,n=50,p=0.3)=0
as x is a continuous distributed
b)
z score at x = 15
x is mean so that z value at x =0
p(x>15,n=50,p=0.3)=0.5
c)
p(x>12,n=50,p=0.3)
Z value at 12
Z = (X - ?) / ?
Z = (12 - 15) / 3.24
Z = -0.92593
From z score table
P(x>12) =P(z> -0.92593) = 0.8228
d)
p(12<x<18,n=50,p,=0.3)
Z value at x =18
Z = (X - ?) / ?
Z = (18 - 15) / 3.24
Z = 0.92593
From z score table
p(12<x<18) = P( -0.92593 < Z < 0.92593) = 0.8228-0.1772= 0.6455
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