A simple random sample of 17 observations is derived from a normally distributed population with a known standard deviation of 3.5.
a. Is the condition that X−X− is normally
distributed satisfied?
b. Compute the margin of error with 99%
confidence. (Round intermediate calculations to at least 4
decimal places. Round "z" value to 3 decimal places and
final answer to 2 decimal places.)
c. Compute the margin of error with 95%
confidence. (Round intermediate calculations to at least 4
decimal places. Round "z" value to 3 decimal places and
final answer to 2 decimal places.)
d. Which of the two margins of error will lead to
a wider interval?
Solution :
(a)
Yes
(b)
Z/2 = 2.576
Margin of error = E = Z/2* ( /n)
= 2.576 * (3.5 / 17)
= 2.19
(c)
Z/2 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (3.5 / 17)
= 1.66
d)
99% confidence interval is wider
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