Researchers in the corporate office of an airline wonder if there is a significant difference between the cost of a flight on Priceline.com vs. the cost of the same flight on the airline's own website. A random sample of 6 flights were tracked on Priceline.com and the airline's website and the mean difference in price (Priceline.com - Airline Site) was $-51.971 with a standard deviation of $11.1065. Create a 99% confidence interval for the true average difference in costs between the vendors.
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Solution :
Given that,
Point estimate = sample mean = = -51.971
sample standard deviation = s = 11.1065
sample size = n = 6
Degrees of freedom = df = n - 1 = 6-1 = 5
At 99% confidence level
= 1-0.99% =1-0.99 =0.01
/2
=0.01/ 2= 0.005
t/2,df
= t0.005,5 = 4.03
t /2,df = 4.03
Margin of error = E = t/2,df * (s /n)
= 4.03 * (11.1065 / 6)
Margin of error = E = 18.28258
The 99% confidence interval estimate of the population mean is,
- E < < + E
-51.971- 18.28258 < < -51.971 + 18.28258
-70.2536 < < - 33.6884
( -70.2536,- 33.6884)
Answer = 5) ( -70.2536,- 33.6884)
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