s = 17.0 lbs.;
Find the standardized (z) score for the data point 205.0 lbs.
Solution :
Given that,
mean = M = 183.5
standard deviation = S = 17.0
n = 8
M = 183.5
SM = S / n = 17.0 8 = 6.0104
a ) Using standard normal table,
The First quartile is,
P(Z < z) = 25%
= P(Z < z) = 0.25
= P(Z < -0.6745 ) = 0.25
z = -0.6745
Using z-score formula,
= z * SM + M
= -0.67 * 6.0104 + 183.5
= 179.47
First quartile =179.5 lbs
b ) = 205.0
Using z-score formula,
Z = - M /SM
= (205.0 -183.5 ) / 6.0104
= 21.5 / 6.0104
=3.577
Z = 3.58
Get Answers For Free
Most questions answered within 1 hours.