A researcher took a random sample of 12 two-slice toasters and found an average price of $53.10 with a standard deviation of $12.90. Assuming we have Normal data, construct a 90% confidence interval for the mean price for two-slice toasters. Also find the margin of error. Round your answers to 2 decimal places.
Solution :
Given that,
t /2,df = 1.796
Margin of error = E = t/2,df * (s /n)
= 1.796 * (12.90 / 12)
Margin of error = E = 6.69
The 90% confidence interval estimate of the population mean is,
- E < < + E
53.10 - 6.69 < < 53.10 + 6.69
46.41 < < 59.79
(46.41 , 59.79)
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