Salary data from two random samples of high school teachers are shown to the right. Also shown are the population standard deviations.
Construct a 90% confidence interval to estimate the difference in the average salaries of the high school teachers in these two states.
b. Based on the results in part? a, can you conclude that a difference exists in the average? salaries?
state A | state B | |
sample mean | 52,236 | 57,231 |
sample size | 43 | 49 |
population standard deviation | 6207 | 6671 |
The confidence interval is ($ ),($ )
?(Round to the nearest dollar as? needed.)
given data
state A | state B | |
sample mean | 52,236 | 57,231 |
sample size | 43 | 49 |
population standard deviation | 6207 | 6671 |
mean of group A
mean of group B
Overall mean of the samples
number of samples in the individual group group =
Total number of sample (n)=43+49=92
No of group (m)=2
Step 1
NOW WITHEN PROPERTY
given that
and
so varience
hence
hence
Step 3 calculate test statistic
test stastistic
step 4 From the table of distribution of probablity we we have to calculate F critical now
so F criticle with respect to degree of freedon (2,92) at
Step 5 conclusion :
Since we found that so we have enough evidence to reject the null hypothesis
hence it is concluded that there is a difference exists between the two given means
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