Question

1. The critical F value with 6 numerator and 40 denominator degrees of freedom at α...

1. The critical F value with 6 numerator and 40 denominator degrees of freedom at α = .05 is

2. Consider the following information.

​

SSTR = 6750 H0: μ1 =μ2 =μ3 =μ4 = μ5
SSE = 8000 Ha: At least one mean is different

​

The null hypothesis is to be tested at the 5% level of significance. The p-value is

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Homework Answers

Answer #1

hypothesis:-

at least one mean is different.

given data are:-

the test statistic is :-

the p value = 0.0003

[ in any blank cell of excel type =F.DIST.RT(5.625,6,40) ]

decision:-

p value = 0.0003 <0.05 (alpha)

so, we reject the null hypothesis .

*** if you have any doubt regarding the problem please write it in the comment box.if you are satisfied please give me a LIKE if possible...

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