SnackType |
Chips |
CandyBars |
Crackers |
Nuts |
PurchaseFrequency |
159 |
218 |
174 |
149 |
What type of test should we perform to test the agent’s belief?
The p-value for the chi-square statistic is 0.021. At the significance level of 0.05, the correct decision and conclusion are (is):
I. Fail to reject the null hypothesis that the births are uniform throughout the year.
II. Reject the null hypothesis that the births are not uniform throughout the year.
III.There is sufficient evidence that the births are not uniform throughout the year.
IV.There is not sufficient evidence that the births are not uniform throughout the year.
A) III only
B) Both II and III
C) Both I and IV
D) I only
E) II only
Age |
||||
Less than 30 |
30-55 |
56 or older |
Total |
|
In-Town Branch |
20 |
40 |
40 |
100 |
Mall Branch |
30 |
50 |
20 |
100 |
Total |
50 |
90 |
60 |
200 |
What type of test are you performing?
Age |
||||
Less than 30 |
30-55 |
56 or older |
Total |
|
In-Town Branch |
20 |
40 |
40 |
100 |
Mall Branch |
30 |
50 |
20 |
100 |
Total |
50 |
90 |
60 |
200 |
What is the expected number of less-than-30-year-old customers coming for service at the branch located near the mall?
Age |
||||
Less than 30 |
30-55 |
56 or older |
Total |
|
In-Town Branch |
20 |
40 |
40 |
100 |
Mall Branch |
30 |
50 |
20 |
100 |
Total |
50 |
90 |
60 |
200 |
The p-value for the chi-square statistic is 0.231. At the significance level of 0.05, the correct decision and conclusion are (is):
14. To check if the observed frequency is different from
expected frequencies, chi-square goodness of fit test should be
conducted.
c) Goodness of fit test is correct
15. The null hypothesis is that the births are uniform
throughout the year.
As p = 0.021, the null hypothesis is rejected.
Hence, there is sufficient evidence that the births are not
uniform throughout the year.
A) III only is correct.
16. Here, we need to check the dependence between two variables
- age and branch
C) Independence test is corrrect
17. Expected number of less than 30 year old customers at mall
branch = 50*100/200 = 25
Hence, A) 25 is correct.
18. The p-value = 0.231, we fail to reject the null hypothesis
that the variables are independent of each other.
Hence, I and IV is correct.
C) option is correct.
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