Question

In a survey of a random sample of 25 households in the Cherry Creek neighborhood of...

In a survey of a random sample of 25 households in the Cherry Creek neighborhood of Denver, it was found that 9 households turned out the lights and pretended not to be home on Halloween.

a) Let p be the proportion of all households in Cherry Creek that pretend not to be home on Halloween. Find, a point estimate for p.

b) Compute a 85% confidence interval for p. What does a 85% confidence interval mean?

c) Check the assumptions necessary to calculate the confidence interval of part b).

Homework Answers

Answer #1

Note-if there is any understanding problem regarding this please feel free to ask via comment box. Thank you

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a survey of a random sample of 35 households in the Cherry Creek neighborhood of...
In a survey of a random sample of 35 households in the Cherry Creek neighborhood of Denver, it was found that 8 households turned out the lights and pretended not to be home on Halloween. (a) Compute a 90% confidence interval for p, the proportion of all households in Cherry Creek that pretend not to be home on Halloween. (Round your answers to four decimal places.) lower limit     upper limit     (b) What assumptions are necessary to calculate the confidence interval...
In a random sample of 67 professional actors, it was found that 42 were extroverts. (a)...
In a random sample of 67 professional actors, it was found that 42 were extroverts. (a) Find a 95% confidence interval for p. (Round your answers to two decimal places.) lower limit     upper limit     In a survey of a random sample of 35 households in the Cherry Creek neighborhood of Denver, it was found that 12 households turned out the lights and pretended not to be home on Halloween (a) Compute a 90% confidence interval for p, the proportion of...
For this problem, carry at least four digits after the decimal in your calculations. Answers may...
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. In a survey of a random sample of 35 households in the Cherry Creek neighborhood of Denver, it was found that 11households turned out the lights and pretended not to be home on Halloween. (a) Compute a 90% confidence interval for p, the proportion of all households in Cherry Creek that pretend not to be home on Halloween. (Round...
For this problem, carry at least four digits after the decimal in your calculations. Answers may...
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. In a survey of a random sample of 35 households in the Cherry Creek neighborhood of Denver, it was found that 14 households turned out the lights and pretended not to be home on Halloween. (a) Compute a 90% confidence interval for p, the proportion of all households in Cherry Creek that pretend not to be home on Halloween....
In a recent survey of 4276 randomly selected households showed that 4020 of them had telephones....
In a recent survey of 4276 randomly selected households showed that 4020 of them had telephones. Using these results, construct a 99% confidence interval estimate of the true proportion of households with telephones. P – PARAMETER Describe the parameter in context. This should be a complete sentence A – ASSUMPTIONS Are we allowed to construct an interval and why? N – NAME THE INTERVAL State what command you will be using the compute the interval along with the values you...
1.A survey of households in a small town showed that in 850 of 1,200 sampled households,...
1.A survey of households in a small town showed that in 850 of 1,200 sampled households, at least one member attended a town meeting during the year. Using the 99% level of confidence, what is the confidence interval for the proportion of households represented at a town meeting? 2.A survey of an urban university (population of 25,450) showed that 750 of 1,100 students sampled attended a home football game during the season. Using the 99% level of confidence, what is...
A survey organization takes a simple random sample of  200 households from a city of 50,000 households....
A survey organization takes a simple random sample of  200 households from a city of 50,000 households. On the average there are  2.3 persons per sample household, and the SD is 1.8. a)  Find a 90%-confidence interval for the average household size in  the city b)  Find a 80%-confidence interval for the average household size in the city. c)  If the researcher decreased the sample size to only 50 people, the length of the  80% confidence interval would be: (i) multiplied by 2        (ii)multiplied by 4         (iii) divided by...
A random sample of 56 households was selected for a phone survey. The key question asked...
A random sample of 56 households was selected for a phone survey. The key question asked was, "Do you or any member of your household own a product from Company A?" of the 56 respondents, 42 say yes and 14 said no. A. determine the same population, p, of households that own a Company A product. B. If the population proportion is 0.75, determine the standard error of the proportion. a. p =
1. A survey of first-time homebuyers found that the sample mean annual income was $46,000. Assume...
1. A survey of first-time homebuyers found that the sample mean annual income was $46,000. Assume that the survey used a sample of 25 first-time home buyers and that the sample standard deviation was $1,100. Compute and explain a 95% confidence interval estimate of the population mean. 2. A telephone poll of 950 American adults asked: "where would you rather go in your spare time?" One response, by 275 adults, was "the Mall". Compute and explain a 99% confidence interval...
2. A survey organization takes a simple random sample of 200 households from a city of...
2. A survey organization takes a simple random sample of 200 households from a city of 50,000 households. On the average there are 2.3 persons per sample household, and the SD is 1.8. a) Find a 90%-confidence interval for the average household size in the city b) Find a 80%-confidence interval for the average household size in the city. c) If the researcher decreased the sample size to only 50 people, the length of the 80% confidence interval would be:...