Question

A variable x is normally distributed with a mean of 2.34 and a standard deviation of...

A variable x is normally distributed with a mean of 2.34 and a standard deviation of 3.4.

Consider the standard normal curve. Find the area between -5.34 and 2.34.

Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that ,

mean = = 2.34

standard deviation = = 3.4

P(-5.34< x < 2.34) = P[(-5.34 - 2.34) /3.4 < (x - ) / < (2.34 - 2.34) /3.4 )]

= P( -2.26< Z < 0)

= P(Z <0 ) - P(Z <-2.26 )

Using z table,  

= 0.5 - 0.0119

area=0.4881

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