Question

Think about a population mean that you may be interested in and propose a hypothesis test problem for this parameter. Gather appropriate data and post your problem and solution in the discussion topic.

For example, you may believe that the population mean number of times that adults go out for dinner each week is less than 1.5. Your data could be that you spoke with 7 people and found that they went out 2, 0, 1, 5, 0, 2, and 3 times last week. You then would choose to test this hypothesis at the .05 (or another level) significance level.

This is the scenario:

In my hypothetical scenario, I am interested in finding the population mean height of men living in my neighborhood. I collected the heights of 10 adult male neighborhood residents (in cm): 160,167,170,171,170,180,182,185,181, and 190. A 95% Confidence Interval for the population mean = ____?

This portion of the problem solved:

t value at 95% = 2.262

mean = 1756.00

std.dev. = 9.35

n =10

CI = mean +/- t *(s/sqrt(n)) = 1756.00 +/- 2.262 *(9.35/sqrt(10)) = (168.911 , 182.289)

Thanks in advance for any help!

Answer #1

Note that you have constructed two-sided 95% CI ,which makes it necessary that you want to conduct a two-sided hypothesis test. You could also conduct one-sided hypothesis test by consructing one-sided CI in the form ( - infinity, a finite number ] or [a finite number, +infinity) for either left-tailed hypo.test or right-tailed test respectively.

Here, we assume that you conduct two-tailed hypo. test. The only thing you need to do is to set up the Null and Alternate hypothesis based on some kind of your own assumption about the height of adult males. For eg. we may assume that population mean adult male height is 180 cm. In this case,

Null Hypo : mu = 180

Alternate: mu not equal to 180

And we already see from the 95% CI that 180 belongs to the 95% CI interval. So we conclude that the population mean adult male height in the neighborhood is 180 cm.

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