In a class of 125 students, 27 are computer science majors, 46
are mechanical engineering majors, 11 are civil engineers and the
rest are general engineering majors. Assume students only have one
major.
Suppose six students from the class are chosen at random what is
the probability none are mechanical engineering majors?
We have given total students n = 125
Out of 125 students 46 are mechanical engineering students.
We are choosing 6 students randomly.
We have asked to find the probability none are mechanical engineering majors.
Therefore P(none are mechanical engineering majors) = 1 - P(All are mechanical engineering majors)
P(All are mechanical engineering majors) = 46C6 / 125C6 = 9366819 / 4690625500
= 0.001996923
P(none are mechanical engineering majors) = 1 - P(All are mechanical engineering majors)
= 1 - 0.001996923
= 0.998003077
Hence the probability that none are mechanical engineering majors is 0.99800 (Rounded to 4 decimal places)
Hope this will help you. Thank you :)
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