Cards are dealt by drawing uniformly at random from a deck of cards without replacement until the first ace appears. What is the chance that at most 3 deals are required given that at most 6 deals were required?
Answer:
Given that:
Cards are dealt by drawing uniformly at random from a deck of cards without replacement until the first ace appears.
1) The required probability is
P(3|6) using Baye's theorem it is
where
P(3) is the probability that at most 3 deals are required and P(6) is the probability that at most 6 deals are required.
P(3) is actually the complement of the event where ace doesn't appear in first 3 deals. So
Similarly for P(6)
So,
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