Question

Four students reported their study time and test score from a statistics course and their data...

Four students reported their study time and test score from a statistics course and their data have been converted into Z scores in the table below. What is Pearson's correlation coefficient from this data set?

Group of answer choices

a.)-.50

b.)-.25

c.).75

d.)-1.00

In what situation would a researcher use a  t-test used instead of a Z-test?

Group of answer choices

a.)When there is only one sample.

b.)When the population standard deviation is unknown.

c.)When the sample size is smaller than 30.

d.)When the population is normally distributed.

If you conduct a two-tailed test at the .05 level of significance, with a degree of freedom of 30, what would be your critical t score on the t distribution?

a.)±2.043

b.)±1.729

c.)2.043

d.)1.729

A researcher tested a research hypothesis that people with diagnosed depression will have REDUCED level of depressive symptoms after a cognitive therapy treatment, as compared to the pre-treatment level of depressive symptoms. The cutoff t value is -1.746 for this one-tailed test. The data analysis yielded a mean change score (post-treatment minus pre-treatment) of -3. If the standard error is 2.0, what is the t statistic and what is the conclusion of the hypothesis test?

Group of answer choices

a.)-1.50; fail to reject the null hypothesis

b.)-1.50; reject the null hypothesis

c.)-1.25; fail to reject the null hypothesis

d.)-1.25; reject the null hypothesis

Homework Answers

Answer #1

1)Since study time and test scores are directly related to each other ( as study time increases test scores also increase) the correlation coefficient will be positive value.

r = 0.75

Negative scores indicate inverse relationship.

2) t test and z assume that population should be normally distributed and both can be used to test single population mean .

Z test assumes that population standard deviation is known.

Correct option : when population standard deviation is unknown.

3) critical value of t for two sided test at df 30 is equal to +- 2.043. When test is two sided it's critical region is equally divided on two sides of distribution. Therefore there are two critical values . Positive critical values are only for right tailed test.

4) t = mean change score/ standard Error

t = -3/2 = - 1.5

| - 1.746 | > | -1.5 | , we fail to Reject Null hypothesis.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A two-tailed hypothesis test is being used to evaluate a treatment effect with α = .05....
A two-tailed hypothesis test is being used to evaluate a treatment effect with α = .05. If the sample data produce a z-score statistic of z = -1.24, then what is the correct decision? Reject the null hypothesis and conclude that the treatment has no effect. Reject the null hypothesis and conclude that the treatment has an effect. Fail to reject the null hypothesis and conclude that the treatment has an effect. Fail to reject the null hypothesis and conclude...
Question #3 A researcher is conducting and experiment to evaluate a treatment that is expected to...
Question #3 A researcher is conducting and experiment to evaluate a treatment that is expected to increase the scores for individuals in a population. If the researcher uses a one-tailed test with ( a = .01), then which of the following correctly identifies the critical region? A. z > 2.33 B. z > 2.58 C. z < 2.33 D. z < 2.58 Question #4 A researcher evaluates a treatment effect using a two tailed hypothesis test with ( a =...
An independent-measures research study uses two samples, each with n = 8 participants. If the data...
An independent-measures research study uses two samples, each with n = 8 participants. If the data produce a t statistic of t = 2.50, then which of the following is the correct decision for a two-tailed hypothesis test? Group of answer choices Reject the null hypothesis with a = .05 but fail to reject with a = .01. cannot answer without additional information Reject the null hypothesis with either a = .05 or a = .01. Fail to reject the...
The average test score for the statistics course is 74%. A professor wants to see if...
The average test score for the statistics course is 74%. A professor wants to see if the average test score for students who are given colored pens on the first day of class is higher. The test scores for the 12 randomly selected students who were given the colored pens are shown below. Assume that the distribution of the population is normal. 81, 61, 86, 63, 74, 91, 62, 70, 80, 94, 70, 87 What can be concluded at the...
For your answers pick one *A researcher was interested in inspecting the effect of classical music...
For your answers pick one *A researcher was interested in inspecting the effect of classical music on stress among New York students. She studied a sample of 30 New York students. She found that z= -3.00. Using a = 0.5(two-tailed), what can she conclude? -Reject the null hypothesis and conclude that classical music has no effect on stress levels -Reject the null hypothesis and conclude that classical music has no effect on stress levels -Failed to reject the null hypothesis...
Some researchers claim that herbal supplements improve human memory. To test this claim, a researcher selects...
Some researchers claim that herbal supplements improve human memory. To test this claim, a researcher selects a sample of n = 25 college students. Each student is given herbal supplements daily for 6 weeks and then all the participants are given a standardized memory test. For the population, scores on the tests are normally distributed with µ = 70 and σ= 15. The sample of n = 25 students had a mean score of M = 75. Can we conclude...
1a The following data were obtained from an independent-measures research study comparing three treatment conditions. I...
1a The following data were obtained from an independent-measures research study comparing three treatment conditions. I II III 2 5 7 5 2 3 0 1 6 1 2 4 2 2 T =12 T =10 T =20 G = 42 SS =14 SS =9 SS =10 ΣX2= 182 Use an ANOVA with α = .05 to determine whether there are any significant mean differences among the treatments. The null hypothesis in words is Group of answer choices a. There...
5) A t test comparing a person's score on a test before and after an intervention...
5) A t test comparing a person's score on a test before and after an intervention yields a p value of .08 (p = .08). What should you do about the null (H0) hypothesis? Group of answer choices a. Reject H0 b. Do not reject H0 c. Accept H0 6)If the null (H0) hypothesis is true, then no difference exists between populations. Group of answer choices True False 7) In an ANOVA, if there is no difference between the groups,...
An SAT prep course claims to improve the test score of students. The table below shows...
An SAT prep course claims to improve the test score of students. The table below shows the scores for seven students the first two times they took the verbal SAT. Before taking the SAT for the second time, each student took a course to try to improve his or her verbal SAT scores. Do these results support the claim that the SAT prep course improves the students' verbal SAT scores? Let d=(verbal SAT scores prior to taking the prep course)−(verbal...
An SAT prep course claims to improve the test score of students. The table below shows...
An SAT prep course claims to improve the test score of students. The table below shows the scores for seven students the first two times they took the verbal SAT. Before taking the SAT for the second time, each student took a course to try to improve his or her verbal SAT scores. Do these results support the claim that the SAT prep course improves the students' verbal SAT scores? Let d=(verbal SAT scores prior to taking the prep course)−(verbal...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT