Question

Given a sample of nine and assuming a two-tailed test, what percent of the area under the appropriate

      t-curve will fall beyond 1.86 standard errors of the mean?

      a. 10                b. 5                  c. 0.10             d. 0.05             e. not given

Answer 1

We need to find

P[ - 1.86*SE < t <   + 1.86*SE ]

= P[ ( - 1.86*SE - mean(X) )/SE  < ( t - mean(X) )/SE < (  ​​​​​​​ + 1.86*SE - mean(X) )/SE ]

= P[ ( - 1.86*SE - )/SE  < ( t- )/SE < (  ​​​​​​​ + 1.86*SE - )/SE ]

= P[ - 1.86*SE /SE  < ( t - )/SE < 1.86*SE/SE ]

= P[ -1.86 < t < 1.86 ]

df = n - 1 = 9 - 1 = 8

At 8 df and t = 1.86

= 0.1

C is the correct option