A customer from Cavallaro's Fruit Stand picks a sample of 4 oranges at random from a crate containing 65 oranges, of which 5 are rotten. What is the probability that the sample contains 1 or more rotten oranges? (Round your answer to three decimal places.)
Let p = proportion of rotten oranges = 5/65 = 0.077
Let X : number of rotten oranges
If n = 4 , we asked P( X 1)
P( X 1) = 1 - P( X = 0)
Using binomial probability
P( X = 0) = n!/ X! * ( n -x)! * px * ( 1- p)n -x
P( X = 0) = 4!/0!*4! *(0.077)0*(0.923)4
P( X = 0) = 0.7258
P( X 1) = 1 - 0.7258
P( X 1) = 0.274
Get Answers For Free
Most questions answered within 1 hours.