Rework problem 24 from section 3.2 of your text, involving the subcommittee. For this problem, assume that the committee contains 6 men and 8 women and that three are selected at random for a subcommittee. What is the probability that the subcommittee consists of 2 men and 1 woman, given that it contains both men and women?
Given that,
Committee has 6 men and 8 women.
Total members= 14
3 are selected for a sub-committee which contains both men and women.
Number of ways of selecting 3 from 14 members= 14C3
We need to find the probability that the subcommittee consists of 2 men and 1 woman.
Number of ways of selecting 2 men from 6 men= 6C2
Number of ways of selecting 1 woman from 8 men= 8C1
The probability that the subcommittee consists of 2 men and 1 woman, given that it contains both men and women
So, required probability= 30/91
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