Question

Average talk time between charges of a recently introduced smartphone was determined to be 4 hours...

Average talk time between charges of a recently introduced smartphone was determined to be 4 hours with a standard deviation of 0.8 hours. The shape of the data distribution is not known.

Required of you: a) Compute the estimated proportion of smartphones that would have a talk time between 2.4 and 5.6 hours.

b) What would your answer be if we were interested in the proportion of smartphones having a talk time of more than 6 hours?

Homework Answers

Answer #1

Ans:

We use Chebyshev's rule,when shape of the data distribution is not known.

a)

2.4 and 5.6 are 2 standard deviations below and above the mean respectively.

k=2

So,the estimated proportion of smartphones that would have a talk time between 2.4 and 5.6 hours

=1-(1/2^2)=1-0.25=0.75

b)6 is 2.5 standard deviation above the mean.

The estimated proportion of smartphones that would have a talk time between 2 and 6 hours

=1-(1/2.5^2)

=0.84

So, 0.16 falls beyond 2 and 6 hrs,hence half of it i.e. 0.08 will fall above 6 hrs.

0.08

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
For a certain type of computers, the length of time between charges of the battery is...
For a certain type of computers, the length of time between charges of the battery is normally distributed with a mean of 50 hours and a standard deviation of 15 hours. John owns one of these computers and want to know the probability that the length of time will be between 50 and 70 hours. Entry to a certain University is determined by a national test.  The scores on this test are normally distributed with a mean of 500 and...
The average time spent sleeping (in hours) for a group of medical residents at a hospital...
The average time spent sleeping (in hours) for a group of medical residents at a hospital can be approximated by a normal distribution, with a mean of 6.1 hours and a standard deviation of 1.0 hours. (Source: National Institute of Occupational Safety and Health, Japan) (a) What is the shortest time spent sleeping that would still place a resident in the top 5% of sleeping times? (b) Between what two values does the middle 50% of the sleep times lie?
On the planet of Mercury, 4-year-olds average 2.9 hours a day unsupervised. Most of the unsupervised...
On the planet of Mercury, 4-year-olds average 2.9 hours a day unsupervised. Most of the unsupervised children live in rural areas, considered safe. Suppose that the standard deviation is 1.7 hours and the amount of time spent alone is normally distributed. We randomly survey one Mercurian 4-year-old living in a rural area. We are interested in the amount of time X the child spends alone per day. (Source: San Jose Mercury News) Round all answers to 4 decimal places where...
Flying time on an old route between 2 cities has a mean value of =5.25 hours...
Flying time on an old route between 2 cities has a mean value of =5.25 hours with standard deviation is =0.6 hours. There are 36 flights on a new route where the mean is hours. Does this indicate that the average flying time for the new route is less than 5.25 hours? Use a 5% level of significance. State the null and alternate hypothesis. Will you use a left tail, right tail or 2 tailed test? Identify the sampling distribution...
The Australian Bureau of Statistics (ABS) has collected data on the part-time employment patterns of full-time...
The Australian Bureau of Statistics (ABS) has collected data on the part-time employment patterns of full-time students in Australia and has found the hours worked to be well approximated by a normal distribution with a mean of 15 hours. (a) If 10% of students work more than 25 hours per week, what is the standard deviation of the number of hours worked by students? (b) What is the probability that a student chosen at random works between 5 and 25...
1. In a study of academic procrastination, it was determined that for a random sample of...
1. In a study of academic procrastination, it was determined that for a random sample of 16 undergrad students at a mid-size public university, the mean time spent studying for the final quiz in an intro statistics course was 7.74 hours with a standard deviation of 3.40 hours. Suppose we wish to compute a 95% confidence interval for the mean time spent studying for the intro statistics final quiz by all students. The margin of error for this confidence interval...
We are interested in the average amount of time De Anza students spend studying statistics each...
We are interested in the average amount of time De Anza students spend studying statistics each week. A survey of 32 De Anza students yields a sample average time of 14.4 hours spent studying statistics per week with a sample standard deviation of 1.9 hours. Conduct a hypothesis test using a 5% level of significance, to determine if the average time spent studying statistics each week by De Anza students is less than 15 hours. 1. Ho: _______________ Ha: ___________________...
4. A sociologist cites a study showing that, in a particular parish, the amount of time...
4. A sociologist cites a study showing that, in a particular parish, the amount of time preschool children ages 3–5 spend watching TV is 22.6 hours per week, with a standard deviation of 6.1 hours. A second researcher doubts these findings, believing that the actual figure is higher. To attempt to resolve the question, a simple random sample of 60 preschool children is chosen, and their TV watching habits are measured by having their parents keep a daily log of...
A. A supermarket claims that the average wait time at the checkout counter is less than...
A. A supermarket claims that the average wait time at the checkout counter is less than 9 minutes.  Assume that we know that the standard deviation of wait times is 2.5 minutes. We will test at 5% level of significance. Consider H0: mu >= 9 H1: mu < 9 A random sample of 50 customers yielded an average wait time of 8.2 minutes. What is the critical value for the Zstat (the Z-test statistic)? (Provide two decimal places)____________ B. Given the...
PSYC 220: Homework 4 Note: In the case of decimals, round to the nearest hundredths place...
PSYC 220: Homework 4 Note: In the case of decimals, round to the nearest hundredths place (ex: 9.37) 1. Alpha is the probability of committing a Type I Error if… a. The null distribution is true b. The null distribution is false c. n is larger than 30 d. the alternative distribution is true 2. We are more likely to reject the null as… a. Alpha goes down b. n goes down c. variation goes down d. the difference between...