The mean annual tuition and fees for a sample of 12 private colleges was with a standard deviation of . You wish to test whether the mean tuition and fees for the population of all private colleges is greater than . Calculate the test statistic value and give its P-value for this test. Assume the population is normally distributed.
Group of answer choices
t = 2.38; 0.01 < P-value < 0.025
t = 2.38; 0.01 < P-value < 0.02
z = 2.38; P-value = 0.0087
z = 2.38; P-value = 0.0174
t = 2.38; 0.02 < P-value < 0.05
Since we are not provided with the population standard
deviation, we will be using a ""
test statistic and its value will be 2.38, as given in the options.
Since the sample size (n) is 12, the degrees of freedom will be = n
- 1 = 11. We are dealing with a "greater than" alternative
hypothesis here, so while calculating the p-value, we will be
concerned with the right tail probability.
The p-value will be = P(t11 > 2.38) = 0.0183.
Hence, our answer is -> t = 2.38; 0.01 <
P-value < 0.02 (or, t = 2.38; 0.01
< P-value < 0.025).
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