Given that, n = 340 and x = 215
=> sample proportion = 215/340 = 0.6324
The null and alternative hypotheses are,
H0 : p = 0.62
Ha : p > 0.62
This hypothesis test is a right--tailed test.
Test statistic is,
=> Test statistic = Z = 0.47
p-value = P(Z > 0.47) = 1 - P(Z < 0.47) = 1 - 0.6808 = 0.3192
=> p-value = 0.3192
Since, p-value is greater than 0.10 significance level, we fail to reject the null hypothesis (H0).
Conclusion : There is not sufficient evidence to support the claim that the use of drugs and alcohol among local high school seniors has increased (or higher than 62%).
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